0.2(0.2-x) 0.01x 1.2x=0.12 20

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16+0.2x=0.25x十9求x!

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计算:(2)(2x-1.5)/0.5-(3x-0.6)/0.2>(0.19-0.3x)/0.01

不等式(2x-1.5)/0.5-(3x-0.6)/0.2>(0.19-0.3x)/0.01可化为:2(2x-1.5)-5(3x-0.6)>19-30x4x-3-15x+3>19-30x-11x>19-

0.2x+0.4x=12 x=?20x+x=420 x=?

0.2x+0.4x=120.6x=12x=12÷0.6x=2020x+x=42021x=420x=420÷21x=20

X-X×0.2=1.18

当然能算出来X-X×0.2=1.18(1-0.2)X=1.180.8X=1.18解得X=1.475

0.5分之x-0.01分之0.2-0.3x=12 ,求x的解

你确定题目没错?结果是-32.0.5分之X化简后是2X,0.01分之0.2化简后是20,0.3X化简后是3X,所以化简后的题目是:2X-20-3X=12,-X=32,X=32

0.1x/0.2-0.01x-0.01/0.06=x-1/3怎么算

1/2X-0.01X-1/6=X-1/31/2X-0.01X-X=-1/3+1/6-0.51X=-1/6X=50/153

x-0.2x=80 求x

x-0.2x=800.8X=80X=100在右上角点击【评价】,然后就可以选择【满意,问题已经完美解决】了.

0.2分之x-0.01分之0.3x=1

因为1/0.2=51/0.01=100所以即5x-100*0.3x=15x-30x=1-25x=1x=-1/25

请问这道题怎解,(X-4)/2+(0.2X-0.3)/0.5=0.02X/0.01

(x-4)/2+(0.2x-0.3)/0.5=0.02x/0.01两边同时乘于2(x-4)+4(0.2x-0.3)=200×0.02xx-4+0.8x-1.2=4xx+0.8x-4x=4+1.2-2.

0.2分之x+1--0.01分之x+3=50

0.2分之x+1--0.01分之x+3=50去分母5(x+1)-100(x+3)=50去括号5x+5-100x-300=50合并同类项-95x=345系数化为1:x=-69/19

(x+8 )/0.2-(x-3)/0.5=2+(0.2x+0.7)/0.01 解方程

方程两边同时乘以15(x+8)-(x-3)=2+10(0.2x+0.7)5x+40-x+3=2+2x+74x+43=2x+92x=-34x=-17

0.4x+0.1-0.04分之0.01-0.2x=5.75

0.5分之0.4x+0.1-0.04分之0.01-0.2x=5.752(0.4x+0.1)-25(0.01-0.2x)=5.750.8x+0.2-0.25+5x=5.755.8x-0.05=5.755

解方程:2-0.1X+0.2/0.5=X-0.01X-0.01/0.02 急啊~~~ 快

2-0.1x+0.2/0.5=x-0.01x-0.01/0.022-0.1x+0.4=0.99x-0.52+0.4+0.5=0.1x+0.99x2.9=1.09xx=2.9/1.09=290/109

化简(2x-5)(3x+2)-6(x+1)(x-2),其中x=0.2

(2x-5)(3x+2)-6(x+1)(x-2)=6x²+4x-15x-10-6(x²+x-2x-2)=6x²-11x-10-6(x²-x-2)=6x²

x+8/0.2-x-3/0.5=2+0.2x+0.7/0.01

(x+8)/0.2-(x-3)/0.5=2+(0.2x+0.7)/0.015(x+8)-2(x-3)=2+100(0.2x+0.7)5x+40-2x+6=2+20x+7017x=-26x=-26/17

解方程0.3x+0.2/0.4-0.05x+0.01/0.02=0.7x-0.1/0.3

(3/10)x+(2/10)/(4/10)-(1/20)x+(1/100)/(2/100)=(7/10)x-(1/10)/(3/10)(3/10)x+1/2-(1/20)x+1/2=(7/10)x-1

如何解0.2x+0.45/0.25-0.015+0.01x/0.1-015=0.5x-2.5

0.2x+1.8-0.015+0.01x/0.1-0.15=0.5x-2.51.8-0.015-0.15+2.5=0.5x-0.2x-0.01x/0.14.135=0.3x-0.01x/0.1*0.1

(1)3x(x+0.2)=4x(x-1.1)

(1)3x(x+0.2)=4x(x-1.1)3x+0.6=4x-4.44x-3x=0.6+4.4x=5(2)乘以0.8得4(1-x)=3x4-4x=3x4=7xx=4/7(7分之4)(3)1.1x1.