2x分之1-x y分之(x平方-y平方
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原式=2xy/(x+y)(x-y)+x(x-y)/(x+y)(x-y)=(2xy+x²-xy)/(x+y)(x-y)=(x²+xy)/(x+y)(x-y)=x(x+y)/(x+y)
(3x的平方+2xy-2分之1x)-(2x的平方-xy+x)=3x+2xy-x/2-2x+xy-x=x+3xy-3x/2
(x分之x的平方-y的平方)乘以(x的平方-2xy+y的平方分之2x)其中x=2y=1=(x^2-y^2)/x*2x/(x-y)^2=(x+y)(x-y)/x*2x/(x-y)^2=2(x+y)/(x
(3x²+2xy-1/2x)-(2x²-xy+x)=3x²+2xy-1/2x-2x²+xy-x=x²+3xy-3/2x
x平方-2x分之x+1分之x平方-1这个有两个“分之”说清楚6x平方分之3x平方+3xy=6x²分之3x(x+y)=2x分之(x+y)再问:3Q,x平方-2x分之x——约分再答:重新问
x平方+y平方+2xy分之x平方-4y平方除以x平方+xy分之2y+x=(x-2y)(x+2y)/(x+y)²·x(x+y)/(x+2y)=x(x-2y)/(x+y)
x/y=1/2y=2x(x^2+2xy+y^2)/(x^2-xy+y^2)=(x^2+2x*2x+(2x)^2)/(x^2-x*2x+(2x)^2)=9x^2/3x^2=3
y分之x=2分之1y=2x所以原原式=(x²-2x²-8x²)分之(x²+4x²+4x²)=-9分之9=-1
原式(-xy/3)²*[xy(2x-y)-2x(xy-y²)]=(x²y²/9)(2x²y-xy²-2x²y+2xy²)
3∵x/y=1/2∴y=2x故(x^2+2xy+y^2)/(x^2-xy+y^2)=(x+y)^2/(x^2-xy+y^2)=(x+2x)^2/(x^2-x·2x+4x^2)=9x^2/(3x^2)=
(2分之1x平方y—2xy+y平方)*3xy=1/2x²y*3xy-2xy*3xy+y²*3xy=3/2x³y²-6x²y²+3xy&sup
(3x²+2xy-x/2)-(2x²-xy+x)=x²+3xy-3x/2
(1)2x平方y分之1+3x平方分之2-4xy平方分之3=6y/(12x^2y^2)+8y^2/(12x^2y^2)-9x/(12x^2y^2)=(6y+8y^2-9x)/(12x^2y^2)(2)x
-1/2x^2+xy-1/2y^2=-1/2(x^2-2xy+y^2)=-1/2(x-y)^2a-1/4-a^2=-1/4(1-4a+4a^2)=-1/4(1-2a)^2
2y-xy分之x的平方-2x=x(x-2)/y(2-x)=-x/y;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,
解2xy²-[3xy²-2(x²y-1/2xy²)]-2x²y=2xy²-(3xy²-2x²y+xy²)-2x
4分之9y再问:不是有两问吗????再答:第二个不知道
y分之x=2分之1y=2x所以原原式=(x²-2x²-8x²)分之(x²+4x²+4x²)=-9分之9=-1
(xy-x的平方)÷xy分之x-y=x(y-x)*xy/(x-y)=-x^2y(x的平方+x分之4x的平方-1)乘(1-2x分之x+1)÷x分之1=[x(x+1)分之(2x+1)(2x-1)]乘(1-
x-y分之2x的平方-y-x分之x的平方-4xy+x-y分之2y的平方-x的平方=2x/(x-y)-(x²-4xy)/(y-x)+(2y-x²)/(x-y)=(2x+x²