2x减8分之x平方减16 其中x等于负2-搜答案-智慧作业帮

原式=(x^2-1)/x÷(x^2+x)/x^2=(x-1)(x+1)/x*x^2/x(x+1)=x-1当x=2时,原式=2-1=1

8-2x分之x的平方-16=[(x+4)(x-4)]/[(-2)(x-4)]=-(x+4)/2把x=-2代入上式得：－1

第一题解方程x+2分之x减x-2分之x+2等于x的平方分之8解是分式同乘（x+2）(x-2)化简在同乘x的方得14x的方＝32x的方＝14分之32＝7分之16在开方得根号7分之4第二提先化简,再求值（

(x+1)(x+2)/(x²+4x+4)×(3x+6)/(2x²-8)×6÷1/(x²-4)=(x+1)(x+2)/(x+2)²×2(x+2)/2(x+2)(x

(x+1)分之1-(x²-6x+9)分之(3-x)÷(x-3)分之(x²+x)=(x+1)分之1-(x-3)²分之[-(x-3)]÷(x-3)分之[x(x+1)]=(x+

原式=(x+1)/x÷(2x²-1-x²)/2x=(x+1)/x÷(x²-1)/2x=(x+1)/x÷(x+1)(x-1)/2x=(x+1)/x*2x/(x+1)(x-1

[(x+2)/(x-2)-(x-4)/(x^2-4x+4)]÷(x^2-1)/(x^2+x)=[(x^2-4)/(x-2)^2-(x-4)/(x-2)^2]*x(x+1)/(x-1)(x+1)=(x^

1/4-{(-4x)^2+2x-8}-(1/2x-1)将x=1/2带入公式=1/4-4-1+8-1/4+1=4公式为4.

(x²+x-2)分之(1+x)÷[x-2+(x+2)分之3]=(x²+x-2)分之(1+x)÷[(x+2)分之(x²-1)]=[(x+2)(x-1)]分之(1+x)×(x

原式=[3x/(x-1)-x/(x+1)]×[(x²-1)/x]={3x(x+1)/[(x-1)(x+1)]-x(x-1)/[(x-1)(x+1)]}×[(x-1)(x+1)/x]=[3x(

（X分之X-1减X+1分之X-2）除以X平方+2X+1分之X平方-X,其中X平方-X-1=0=[((x-1)(x+1)-x(x-1)]/x(x+1)÷(x²-x-1+1)/(x+1)

(1)x(x+1)/(x+1)(x-1)=x/x-1(2)(x-3)^22.x^2-8x+16/x^2-16=(x-4)^2/(x+4)(x-4)=x-4/x+4=11/193.是2a/a^2-4和1

X平方-6X+9分之X平方-4=x(x-6)+1/9(x^2-36)=x(x-6)+1/9(x+6)(x-6)=(x-6)[x-1/9(x+6)]=1/9(x-6)(9x-x-6)=1/9(x-6)(

/>（2x-x分之1+x的平方）除以x分之x-1,其中x=根号2=[2x²-(1+x²)]/x÷(x-1)/x=(x²-1)/(x-1)=(x-1)(x+1)/(x-1)

(x²-16)/(x²+8x+16)+x/(x-4)=(x+4)(x-4)/(x+4)²+x/(x-4)=(x-4)/(x+4)+x/(x-4)=(x-4)²/

9+6+1/9-3+1=13又9分之1

X²-X/X²-2X+1-X/X+1=X(X-1)/(x-1)²-X/X+1=X/X-1-X/X+1=2/2-1-2/2+1=2-2/3=4/3