2x-2xy 2(x xy-6)-12
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/10 06:17:51
(x+y)(xy)=x^2y+xy^2=-8原式=-7
(3x2y-2xy2)-(xy2-2x2y)=3x2y-2xy2-xy2+2x2y=5x2y-3xy2当x=-1,y=2时,原式=5×(-1)2×2-3×(-1)×22=10+12=22.
因为化学反应速率是由慢反应决定的
由题意得,x-1=0,y+3=0,解得x=1,y=-3,所以,1-xy-xy2=1-1×(-3)-1×(-3)2,=1+3-9,=4-9,=-5.
原式=(4x2y+5xy2+3x-2y+5)-2(2x2y-3xy2-2x+1)=4x2y+5xy2+3x-2y+5-4x2y+6xy2+4x-2=11xy2+7x-2y+3.
把X=3;Y=-2代入即可解
2(xy-5xy2)-(3xy2-xy)=(2xy-10xy2)-(3xy2-xy)=2xy-10xy2-3xy2+xy=(2xy+xy)+(-3xy2-10xy2)=3xy-13xy2,∵(x+1)
解-x²y-xy²=-xy(x+y)=-2×5=-10
是不是求:5x²y-[2x²-(3xy-xy²)-3x²]-2xy²-y²再问:是再答:已知是不是(x+3)²+|x+y+10|=
(2x3-3x2y-2xy2)-(x3-2xy2+y3)+(-x3+3x2y-y3)=2x3-3x2y-2xy2-x3+2xy2-y3-x3+3x2y-y3=-2y3=-2×(-1)3=2.因为化简的
3xy(x²y-xy²+xy)-xy²(2x²-3xy+2x)=3x³y²-3x²y³+3x²y²-
原式=x3+3x2y-5xy2+6x3+1-2x3+y3+2xy2+x2y+2-4x2y-7x3-y3+4xy2+1=-2x3+xy2+4,由于y为偶次幂,故误把“x=3,y=-1”写成“x=3,y=
1=x+2y=x+y+y≥3(xy²)^(1/3).===>xy²≤1/27.等号仅当x=y=1/3时取得,∴(xy²)max=1/27
(3xy2-6x2y)÷(-2x),=-(3÷2)x1-1y2+(6÷2)x2-1y,=-32y2+3xy.
原式=5xy2-2x2y+3xy2-2x2y=8xy2-4x2y,∵(x-2)2+|y+1|=0,∴x-2=0,y+1=0,即x=2,y=-1,则原式=16+16=32.
原式=2x2y-2xy2-[-3x2y2+3x2y+3x2y2-3xy2]=2x2y-2xy2+3x2y2-3x2y-3x2y2+3xy2=2x2y-3x2y-2xy2+3xy2+3x2y2-3x2y
A-B=(x3+2y3-xy2)-(﹣y3+x3+2xy2)=x³+2y³-xy²+y³-x³-2xy²=3y³-3xy²
原式=2x2y-2xy2+3x2y2-3x2y-3x2y2+3xy2=-x2y+xy2,当x=-12,y=2时,原式=-(−12)2×2+(-12)×22=-52.
解3xy²-[2xy²-2(xy-1.5x²y)]+xy-3x²y=3xy²-(2xy²-2xy+3x²y)+xy-3x²