2m 5n=-8 4m-2n=5

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已知 m/n=5/3,求m/m+n +m/m-n -n^2/m^2-n^2的值 已知1/a+1/b=8/a+b,求b/a

1、=〔m(m-n)+m(m+n)-n^2〕/(m^2-n^2)=(m^2-mn+m^2+mn-n^2)/(m^2-n^2)=〔m^2/(m^2-n^2)〕+1=〔1/(m^2-n^2)/m^2〕+1

计算[5(m+n)2(m-n)]3÷【3(m+n)2(n-m)]2

[5(m+n)2(m-n)]3÷【3(m+n)2(n-m)]2=125(m+n)的6次方(m-n)³÷9(m+n)的4次方(m-n)²=125/9(m+n)²(m-n)如

4m−2n+5=03n−4m=6

由题意4m−2n=−5①3n−4m=6②,方程①+②得,3n-2n=1,∴n=1,把n=1代入①得,4m-2=-5,∴m=-34,∴方程组的解为m=−34n=1.

(m+5n)^2-2(5n+m)(n-3m)+(3m-n)^2

(m+5n)^2-2(5n+m)(n-3m)+(3m-n)^2=(m+5n)^2-2(m+5n)(n-3m)+(n-3m)^2=[(m+5n)-(n-3m)]^2=(4m+4n)^2=16(m-n)^

已知m,n是有理数,且(5+2)m+(3−25)n+7=0

∵(5+2)m+(3-25)n+7=(m-2n)5+2m+3n+7=0,∴m-2n=0,且2m+3n+7=0,联立解得:m=-2,n=-1.

计算:5(m+n)(m-n)-2(m+n)^2-3(m-n)^2

5(m+n)(m-n)-2(m+n)^2-3(m-n)^2=5(m^2-n^2)-2(m^2+2mn+n^2)-3(m^2-2mn+n^2)=5m^2-5n^2-2m^2-4mn-2n^2-3m^2+

一道数学题m+n/2+m-n/3=6 ,4(m+n)-5(m-n)=2

第一个式子:6m+3n+6m-2n=36化简得:12m+n=36第二个式子:4m+4n-5m+5n=2,化简得:9n-m=2,m=9n-2带入第一个化简得式子得:m=332/109,n=60/109你

m,n满足|m+2|+n−9=0

由题意,得m+2=0n−9=0,解得m=-2,n=9.∴(x2+y2)-(-mxy+n)=x2+y2-(-2xy+9)=x2+y2+2xy-9=(x+y)2-9=(x+y+3)(x+y-3).

(n-m)^3×(m-n)^2-(m-n)^5

(n-m)^3×(m-n)^2-(m-n)^5=-(m-n)^3*(m-n)^2-(m-n)^5=-(m-n)^5-(m-n)^5=-2(m-n)^5

若|m+n-5|+(2m+3n-5)²=0,求(m+n)²的值.

由题意得m+n-5=02m+3n-5=0解得n=-5,m=10,∴(m+n)²=(10-5)²=25如果满意记得采纳哦!你的好评是我前进的动力.(*^__^*)嘻嘻……我在沙漠中喝

/m-6/+/n+5/=0则-m+n-3分之2=

M=6,N=-5原式=-6-5-2/3=-11又3分之2

因式分解(n-m)^3(m-n)^2-(m-n)^5

解原式=-(m-n)³(m-n)²-(m-n)^5=-(m-n)^5-(m-n)^5=-2(m-n)^5

1/3m-3/2n-5/6n-1/6m,其中m=6,n=2

1/3m-3/2n-5/6n-1/6m=1/6m-8/3n=1-16/3=-13/3

5(m+n)(m-n)-2(m+n)平方-3(m-n)平方

5(m+n)(m-n)-2(m+n)平方-3(m-n)平方=5m^2-5n^2-2m^2-4mn-2n^2-3m^2+6mn-3n^2=2mn

已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))

已知m=5n,则原式=(5n/(5n+n))+(5n/(5n-n))-(n^2)/(((5n)^3)-n^2)=(5/6)+(5/4)-[1/(125n-1)]=(25/12)-[1/(125n-1)

(m-5n)(m-n)-6(m+2n)(m-3n)

原式=(m²-mn-5mn+5n²)-6(m²-3mn+2mn-6n²)=(m²-6mn+5n²)-6(m²-mn-6n²

(n-m)^3•(m-n)^2•(m-n)^5=计算

再答:如果满意,请点击右上角的满意,谢谢!

[5m(3m-n)+2n(n-3m)]/(3m-n)

[5m(3m-n)+2n(n-3m)]/(3m-n)=[5m(3m-n)-2n(3m-n)]/(3m-n)=(5m-2n)(3m-n)/(3m-n)=5m-2n

[2(m+n)^5-3(m+n)^4+(-m-n)^3]÷[2(m+n)^3]

原式=2(m+n)^5÷[2(m+n)^3]-3(m+n)^4÷[2(m+n)^3]+(-m-n)^3÷[2(m+n)^3]=(m+n)^2-3(m+n)/2-1/2再问:��Ҳ�㵽��һ���ˣ��