27X+9y=23X+6y

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9(x-y)^2-6(y-x)^2+1

9(x-y)^2-6(y-x)+1=9(x-y)^2+6(x-y)+1=[3(x-y)+1]^2=(3x-3y+1)^2

已知实数x,y满足x=√(9-x+2y)+√(3x-6y-27)+5,则-2x-y的立方根为

∵实数x,y满足x=√(9-x+2y)+√(3x-6y-27)+5∴9-x+2y≥0,3x-6y-27≥0∴9≥x-2y,x-2y≥9即9≦x-2y≦9∴x-2y=9∴x=√(9-x+2y)+√(3x

[6(x-y)的3次方*(x+y)的4次方-9*(x-y)的平方*(x+y)的3次方]根号[3(x-y)(x+y)]

6*(x+y)^7-9*(x+y)^3*(x-y)^2*((3*x-3*y)*(x+y))^(1/2)ok?再问:可不可以写清楚点

x^2-9y^2-2x+6y

=(x-1)^2-(3y-1)^2=(x-1+3y-1)(x-1-3y+1)=(x+3y-2)(x-3y)

已知方程组{3x+4y=9 6x+5y=27,则代数式x+y=?

第一个3(x+y)+y=9第二个5(x+y)+x=27两式相加9(x+y)=36得x+y=4

计算:(x-y)^2*(y-x)^2*(x-y)^6

(x-y)^2*(y-x)^2*(x-y)^6=(x-y)^2*(x-y)^2*(x-y)^6=(x-y)^10再问:能详细一点吗?我,初一的再答:(x-y)^2=(y-x)^2=(x-y)^2*(x

(x-y)³+9(x-y)-6(x-y)²

原式=(x-y)[(x-y)^2-6(x-y)+9]=(x-y)(x-y-3)^2很高兴为您解答,祝你学习进步!不懂可追问!

(x-y)x^6+(y-x)y^6因式分解

(x-y)x^6+(y-x)y^6=(x-y)x^6-(x-y)y^6=(x-y)(x^6-y^6)=(x-y)(x³+y³)(x³-y³)=(x-y)(x+y

6(x+y)2-2(x-y)(x+y)因式分解

(x+y)ˆ2-2(x+y)(x-y)+(x-y)ˆ2=(x+y-x+y)^2=(2y)^4=4y^2如果满意请点击右上角评价点【满意】即可~再问:这个我看不懂,能不能写下来啊,谢

若:x+2y=62x+y=9

方法一:(1)×2-(2)得:3y=3,y=1.将y=1代入(1)得:x+2=6,x=4.∴x+y=1+4=5x+y=5.方法二:两个方程相加,得3x+3y=15,x+y=5.

(三分之二x√9x +6x√x/y)+(y√y/x -x²√x/1)

y/x哪个是分子?按理说y/x应该是x分之y,即y是分子再问:x是分子啊二次根式化简。。。。再答:注意应是分子/分母分子在前面的我前面都是按这个做的显然x>0,y>0则原式=(2x/3)*3√x+6x

已知x平方-6x+9与/y-1/互为相反数,计算(x/y-y/x)÷( x+y)

x平方-6x+9与/y-1/互为相反数(x-3)²+|y-1|=0x-3=0y-1=0x=3y=1(x/y-y/x)÷(x+y)=(3-1/3)÷(3+1)=2/3

{(x,y) |x|+|y|

区域是一个正方形

已知方程组3x+4y=9,6x+5y=27,则11x+11y=

3x+4y=96x+5y=27两式相加得:9x+9y=36则:9(x+y)=36所以,x+y=4所以,11x+11y=11(x+y)=44

化简:x-y/x+3y÷x^-y^2/x^2+6xy+9y^2-(xy/x+y)

[(x-y)/(x+3y)]/[(x^2-y^2)/(x^2+6xy+9y^2)]-xy/(x+y)=(x-y)/(x+3y)*(x+3y)^2/(x-y)(x+y)-xy/(x+y)=(x+3y)/

9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y的平方(x-y)(x+1),因式分解

第一项与第三项先合并9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y^2*(x-y)(x+1)=(x-y)(x+1)(9xy+6y^2)-3y(x-y)(3x+2y)=(x-y)(x+1

计算:(2/3x√9x+6x√y/x)+(y√x/y-√1/x)

(2/3x√9x6x√y/x)(y√x/y-x²√1/x)=2/3*x*3√x6x*√(xy)/xy*√(xy)/y-x²√x/x=2x√x6√(xy)√(xy)-x√x=x√x7

x+y=6005x%+8y%=600×6%

方程组整理得:x+y=600①5x+8y=3600②,②-①×5得:3y=600,即y=200,将y=200代入①得:x=400,则方程组的解为x=400y=200.

{4/(x+y)+6/(x-y)=3 {9/(x-y)-1/(x+y)=1

完整设1/(x+y)=a,1/(x-y)=b原方程组可变为4a+6b=39b-a=1a=9b-136b-4+6b=3b=1/6,a=1/2x+y=2x-y=6所以原方程组的解为:x=4,y=-2

x>y?x:y

判断X的数值是否大于Y的数值如果是则为真等式去X的值反之取Y的值