化简求值已知x=2 根号3分之1
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x^2-9>=09-x^2>=0x=3或-3x=3不合题意,舍去x=-3y=(0+0+1)/(-3-3)=-1/6
解:原式=(x-y)×(xy)分之(xy)的平方-(x-y)的平方乘以(x的平方×y的平方)分之(y的平方-x的平方)=-(xy分之4)当x=2根号3,y=2-根号3时;代入-(xy分之4),结果为5
x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1=[x/(x+2)-(x²+2x+1)/(x+2)]÷(x²-1)/(x-1)=[(x-x²-2x-1)/
(x-1分之x平方-1-x分之2x)除以x-1分之x,其中x=根号3+1=[x²/(x-1)+2x/(x-1)]÷x/(x-1)=x(x+2)/(x-1)*(x-1)/x=x+2其中x=根号
只有我能看懂吧?!再答: 再答:题是这样的吗?再答: 再问:你终于回来了再问:在吗再答:在再问:等等我去写题再问:去吧
原式=(x²-1-15)/(x-1)×(x-1)/(x-4)=(x²-16)/(x-4)=x+4当x=√3-4时原式=√3
原式=[(√x-√y)²+(√x+√y)²]/(√x+√y)(√x-√y)=(x+y-2√xy+x+y+2√xy)/(x-y)=2(x+y)/(x-y)=2(2+√3)/(2-√3
根号x^2+x^2分之1-2=√(x-1/x)²=lx-1/xl=l1/2-2l=3/2第二题2-x≥0x≤2x-2≥0x≥2所以x=2y+1=0+0y=-1√x+y=√2-1=√1=1再问
(x-1-x+1分之8)除以x+1分之x+3=(x²-1-8)/(x+1)×(x+1)/(x+3)=(x+3)(x-3)/(x+1)×(x+1)/(x+3)=x-3=3-√2-3=-√2
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原式=2x/(x+y)(x-y)-(x+y)/(x-y)(x+y)=(2x-x-y)/(x+y)(x-y)=(x-y)/(x+y)(x-y)=1/(x+y)=1/(3√5-1-2√5+1)=1/√5=
(x-x分之1)除x分之x+1=(x²-1)/x÷(x+1)/x=(x+1)(x-1)÷(x+1)=x-1=√2+1-1=√2本题有什么不明白可以追问,
a=根号2-1∴a-1
(x-1分之3x-x+1分之x)*x分之x的平方-1=[3x(x+1)-x(x-1)]/x=3(x+1)-(x-1)=3x+3-x+1=2x+4=2√2-4+4=2√2再问:确定么再答:确定啊,楼下也
[3x/(x-1)-x/(x+1)]×(x²-1)/x=x[3(x+1)-(x-1)]/(x²-1)×(x²-1)/x=2x+4当x=√2-2时,原式=2x+4=2√2
原式=(x-2+2x+4)/(x+2)(x-2)*x(x+2)/3x+2)=x/(x-2)当x-2+根号3时,原式=(2+根号3)/(2+根号3)-2=(2根号3+3)/3
5x=-3yx=-3|5y直接带进去得答案,或者=2\3x-2|3x+2|x+y的和乘(x+y)除以x-y|x=2乘x\x-y=2(-3\5y)\(-3\5y-y)=3\4手机果然不行.
x=﹙2+√3﹚/﹙2-√3×=﹙2+√3﹚²=7+4√3y=﹙2-√3﹚/﹙2+√3﹚=﹙2-√3﹚²=7-4√3x·y=﹙7-4√3﹚×﹙7+4√3﹚=1x+y=7+4√3+7