化简求值 (1-x-1分之1)÷x的平方 4x 4分之x的平方-4

题目有误吧(x-x)x-1分之4(x-x)+(x-2)再问：(x方-x)(x-2)方再答：

是(x^2/(x-1)-x+1)/(4x^2/(1-x)-4x+1)吗原式=(x-x+1)(x+x-1)/(x-1)/((4x^2-4x+1+4x^2-x)/(1-x))=-(2x-1)/(4x^2-

[1/(x-y)-1/(x+y)]÷2y/(x^2-2xy+y^2)=[(x+y)/(x+y)(x-y)-(x-y)/(x+y)(x-y)]÷2y/(x-y)^2=[(x+y-x+y)/(x+y)(x

第一题原试=(4/(x-2)(x+2)-(x+2)/((x-2)(x+2)))*(x-2)=(2-x)/((x+2)(x-2))*(x-2)=(2-x)/(x+2)带入x=2013=-2011/201

【先化简再求值】（x-1）分之x÷【(1-x分之1）-1-x】=（x-1）分之x÷（x^2/(1-x)）=-1/xx=1时,原式无意义,x=2时,原式=-1/2,x=0时,原式无意义【选择题】下列约分

原式=(x²-1-15)/(x-1)×(x-1)/(x-4)=(x²-16)/(x-4)=x+4当x=√3-4时原式=√3

(x-4)(2x-5)-(3x-2)(x+6)=(2x²-13x+20)-(3x²+16x-12)=2x²-13x+20-3x²-16x+12=-x²

=(x+1)(x-1)/x÷(x-2x+1)/x=(x+1)(x-1)/x×[-x/(x-1)==x+1当x=√2时原式=√2+1再问：对不起，是我没说明白x²-1÷(1-x分之2x-1)是

（x-1-x+1分之8）除以x+1分之x+3=(x²-1-8)/(x+1)×(x+1)/(x+3)=(x+3)(x-3)/(x+1)×(x+1)/(x+3)=x-3=3-√2-3=-√2

(x-x分之1)除x分之x+1=(x²-1)/x÷（x+1)/x=(x+1)(x-1)÷(x+1)=x-1=√2+1-1=√2本题有什么不明白可以追问,

1/x+1+1/x-1.(x+1)(x-1)-x2+2x/x+2.(x-1)/x上式约分得到x-1=?x=2012即值为2011再问：没看明白唉→_→再答：电脑打不出格式来，所以看起来很麻烦。X的平方

结果-34,太简单了.

[(2x-y)²-y(y-4x)-8x]÷(2x)=[4x²-4xy+y²-y²+4xy-8x]÷(2x)=[4x²-8x]÷(2x)=2x-4将x=

原式=（x-2+2x+4)/(x+2)(x-2）*x(x+2)/3x+2)=x/(x-2)当x-2+根号3时,原式=（2+根号3）/（2+根号3）-2=（2根号3+3）/3

{1-x/(x-1)}÷1/x(x-1)=(x-1-x)/(x-1)÷1/x(x-1)=-1/(x-1)÷1/x(x-1)=-x

（x+1）÷[2+x分之(1+x²)]=（x+1）÷[x分之(2x+1+x²)]=(x+1)÷[x分之(x+1)²]=(x+1)·[(x+1)²分之x]=(x+

=(x²-1)/(x²-2x)-(x-1)/(x²-2x)=(x²-1-x+1)/(x²-2x)=(x²-x)/(x²-2x)=x

[4(x^2+y)(x^2-y)-(2x^2-y)^2]÷y=[4(x^4-y²)-(4x^4-4x²y+y²)]÷y=[4x^4-4y²-4x^4+4x

[（x+2)/x-(x-1)/(x-2)]÷（x-4)/x=[1+2/x-1-1/(x-2)]×x/(x-4)=(x-4)/x(x-2)×x/(x-4)=1/(x-2)=1/(3-2)=1这是我在静心

(x+1分之1+x-1分之1)·(x平方-1)=x+1分之1·(x平方-1)+x-1分之1·(x平方-1)=x-1+x+1=2x