化简m²-9分之12
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(m²-3m)/(9-m²)=m(m-3)/(3+m)(3-m)=-m/(m+3);您好,很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,如果满意
m^2-12/9-m-2/3=m^2-m-2=(m-2)(m-1)
12/(m²-9)-2/(m-3)=12/(m²-9)-2(m+3)/(m²-9)=[12-2(m+3)]/(m²-9)=-2(m-3)/(m²-9)
=(m-15)/(m+3)(m-3)-2(m+3)/《-(m-3)(m+3)》=m-15+2m+6/(m+3)(m-3)=3m-9/(m+3)(m-3)=3(m-3)/(m+3)(m-3)=3/(m+
=m(m+n)/(m-n)×m/(m+n)-n²/(m-n)=m²/(m-n)-n²/(m-n)=(m²-n²)/(m-n)=(m+n)(m-n)/(
m的平方-9分之12)-(m-3分之2)=m²-3分之4-m+3分之2=m²-3分之2-m再问:先通分,化为同分母分式再加减,求~再答:要不你打清楚些分母是哪个?加[]吧你这么打有
3m-12分之m的平方-16=3(m-4)分之(m+4)(m-4)=3分之(m+4)
12/(m^2-9)+2/(3-m)+2/(m+3)=12/(m^2-9)-2/(m-3)+2/(m+3)=12/(m^2-9)-2(m+3)/(m^2-9)+2(m-3)/(m^2-9)=[12-2
(m+2分之2m-m-2分之m)除以m的平方-4分之m=m*(2/(m+2)-1/(m-2))*(m^2-4)/m=(2/(m+2)-1/(m-2))*(m+2)(m-2)=2(m-2)-(m+2)=
4m的平方—9分之2m的平方+m—3=(2M+3)(2M-3)分之(2M+3)(M-1)=(2M-3)分之(M-1)再问:x-1分之x-3除以x的平方+2x+1分之x-3-x-1分之1化简后代入x=根
原式=-8m/5+2
化简m的平方减去9分之m的平方减去3m+m+3分之3=m方-(m/9)方-(3m+m+1)=m方-(m/9)方-4m-1=80m方-324m-81
(1+n/m-m/m-n)=m(m-n)+n(m-n)-m]/[m(m-n)]=(m^2-n^2-m)/[m(m-n)](1-n/m-m/m+n)=m(m+n)-n(m+n)-m]/[m(m-n]=(
(M-3分之1)(M的平方+9分之1)(M+3分之1)=(M-3分之1)(M+3分之1)(M的平方+9分之1)=(M²-9分之1)(M²+9分之1)=M的4次方-81分之1很高兴为
12/(m^2-9)+2/(3-m)+2/(m+3)=12/(m^2-9)-2/(m-3)+2/(m+3)=12/[(m-3)(m+3)]-2(m+3)/[(m-3)(m+3)]+2(m-3)/[(m
原式=m^2-n^2/m-n=(m+n)(m-n)/m-n=m+n很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,
原式=-(m²-9)分之(m²-3m)=-(m+3)(m-3)分之m(m-3)=-(m+3)分之m
解由-m√(-1/m)知m<0故-m√(-1/m)=-m√(-1×m/m×m)=-m√(-1×m/m^2)=-m×1//m/×√(-1×m)=-m×1/(-m)×√(-1×m)=1×√(-1×m)=√
=12/(m+3)(m-3)-2/(m-3)+1/(m+3)=12/(m+3)(m-3)-2(m+3)/(m+3)(m-3)+(m-3)/(m+3)(m-3)=(12-2m-6+m-3)/(m+3)(
=12/(m+3)(m-3)-2/(m-3)=12/(m+3)(m-3)-2(m+3)/(m+3)(m-3)=(12-2m-6)/(m+3)(m-3)=-2(m-3)/(m+3)(m-3)=-2/(m