化简(2分之x+y)的平方+(2分之x-y)的平方,得-搜答案-智慧作业帮

3x^2+xy-2y^2=(3x-2y)(x+y)=0x=-2y/3,或x=-y但由于你要求的式子中分母里有X平方-Y平方x=-y舍去其他就代入吧

原式=2xy/(x+y)(x-y)+x(x-y)/(x+y)(x-y)=(2xy+x²-xy)/(x+y)(x-y)=(x²+xy)/(x+y)(x-y)=x(x+y)/(x+y)

(x+y)²/2+(x-y)²/2=(x²+2xy+y²+x²-2xy+y²)/2=(2x²+2y²)/2=x²

（x的平方-y的平方)分之2xy+(x+y)分之x-(y-x)分之y=（x的平方-y的平方)分之2xy+(x+y)分之x+(x-y)分之y=(x²-y²)分之[2xy+x(x-y)

=-(x+2y)(x-2y)/(x+y)²×2x(x+y)/(x-2y)=-2x(x+2y)/(x+y)=-(2x²+4xy)/(x+y)

（x分之x-y）-（y分之x+y）+（2xy分之x的平方-y的平方）=1-y/x-1-x/y+(x^2-y^2)/2xy=-2(y^2+x^2)/2xy+(x^2-y^2)/2xy=-(x^2+3y^

樱桃_小纯子：(x²-2xy+y²-1)/(x-y-1)=[(x-y)²-1]/(x-y-1)=[(x-y+1)(x-y-1)]/(x-y-1)=x-y+1

原式=[2x/(x-y)]*[y/(x+y)]-[x^4/(x^4-y^4)]/[x^2/(x^2+y^2)]^2=2xy/(x^2-y^2)-(x^2+y^2)^2/[(x^2+y^2)(x^2-y

=(x+y)(x-y)/(x+y-1)(x-y+1)×(x-y+1)(x-y-1)/(x+y)²×(x+2y)(x-y)/x(x-y)=(x-y-1)(x+2y)(x-y)/x(x+y-1)

2/(x-y)-(x+y)/(x-y)^2=[(2x-2y)-(x+y)]/(x-y)^2=(x-3y)/(x-y)^2

(x^2-4y^)\(x+y)^2乘以2x(x+y)/(x+2y)=2x(x-2y)\(x+y)

（x/2y）²×（y/2x）-x/y²÷（2y²/x）=x²/2y×（y/2x）-（x/y²）×（x/2y²）=x/8y-x²/（

原式=-(x+2)(x-2)分之xy(x-2)=-(x+2)分之xy

原式=[(x+y)/(x-y)]^2*[2(x-y)/5(x+y)-[X/(x^2y^2)]/[x/(x+y)]=2/5-[x/(x^2y^2)]*[(X+y)/x]=2/5-(x^2y^2)/(x+

平方差=[(3x-2y)/2+(3x+2y)/2][(3x-2y)/2-(3x+2y)/2]=[(3x-2y+3x+2y)/2][(3x-2y-3x-2y)/2]=3x*(-2y)=-6xy

2y-xy分之x的平方-2x=x（x-2）/y(2-x)=-x/y;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,

x的平方-64y的平方分之2x-x-8y分之1=[2x-(x+8y)]/(x-8y)(x+8y)=(x-8y)/(x-8y)(x+8y)=1/(x+8y)

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x-y分之2x的平方-y-x分之x的平方-4xy+x-y分之2y的平方-x的平方=2x/(x-y)-(x²-4xy)/(y-x)+(2y-x²)/(x-y)=(2x+x²