作业帮22X×0.12÷0.75 100000=12X-1000000方式式解析
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[（x+2）/（x*x-2x）-（x-2）/（x*x-4x+4）]/[(x-4)/x]=[（x+2)/x(x-2)-(x-2)/(x-2)²]/[(x-4)/x]=[(x²-4-x
=（x+1）(x-1)(x+1)x-1--------------÷------×-----(x-1)^2(x-1)x+1=x+1---x-1
(x+1-1/1-x)÷(x-x²/x-1)=[(x+1)+1/(x-1)]×[-(x-1)/x(x-1)]=(x²-1+1)/(x-1)×(-1/x)=-x/(x-1)(x-4/
原式=x−22(x−3)÷−(x−2)(x+2)x−3=x−22(x−3)×x−3−(x−2)(x+2)=1−2(x+2)，当x=2-2时，原式=-122=-24．
解题思路：分式的混合运算，按照分式运算法则进行计算。解题过程：
先化简去掉中括号：(1-x+x-1/x)÷(1-1/x-1)再化简：(1-1/x)÷(-1/x)=(1-1/x)x(-x)=1-x
(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)=2（x-3)/(x-2)^2X(x+3)^2/(3-x)X(2-x)/(x+3)=2（x-
原式=x−22(x+1)×x+1(x+2)(x−2)=12x+4；∵x=tan60°-2=3-2，∴原式=12x+4=123=36．
(x²-4x+4)/(x²-2x)÷(x-4/x)=(x-2)²/[x(x-2)]÷[(x²-4)/x]=(x-2)²/[x(x-2)]÷[(x+2)
/>(4X+2)/X+【4(X-5)-2】/(X-5)=【(X-4)-2】/(X-4)+【7(X+1)+2】/(X+1)4+2/X+4-2/(X-5)=1-2/(X-4)+7+2/(X+1)8+2/X
(x-22)+(x-24)+(x-27)+(x-20)=xx-22+x-24+x-27+x-20=x4x-93=x4x-x=933x=93x=31
8.4x-x=0.127.4x=0.12x=0.01621621621621621621621621621622162是无限循环.
2x/(x-2)(x+1)÷(1－x/x+1)-x²+2x/x²-4?=2x/(x-2)(x+1)×(x+1)/(1-x)-x(x+2)/(x+2)(x-2)=2x/(x-2)(1
=【3x(x+1)-x(x-1)]/(x+1)(x-1)×(x+1)(x-1)/x=(3x²+3x-x²+x)/x=4
x-4x=102-3x=102x=-34x-0.8x=220.2x=22x=110
[3x/(x+2)-x/(x-2)]÷2x/(x^2-4)分子分母同时乘以x²-4=[3x(x-2)-x(x+2)]/2x=(3x²-6x-x²-2x)/2x=(2x&#
2.4/0.12*6.6=132
x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)=x((2x-1)/x)+x/(x^2-2x)x(x^2-4)/(3-x)=(2x-1)+(x+2)/(3-x)=(7x-3-2x^2
你的括号丢得太多了,我猜猜猜1、实在猜不出来,哪里该有括号2、2X/(2X-1)+X/(X-2)=2[2X(X-2)+X(2X-1)]/(2X-1)(X-2)=22X^2-4X+2X^2-X=4X^2