利用随机函数产生10个1到100之间的随机数,显示出最大值

窗体中加命令按钮,单击事件代码如下：PrivateSubCommand1_Click()  Randomize  Dima(1To20)AsInteger&nb

函数不对,正确的应为randbetween()=randbetween(0,50)=randbetween(-2,6)带正负号

a1:a10=randbetween(30,100)最大值=max(a1:a10)最小值=min(a1:a10)平均值=average(a1:a10)

PrivateSubCommand1_Click()RandomizeDima(10)AsInteger,imasasinteger,iminasinteger,Averageasintegerima

PrivateSubCommand1_Click()Dimi,max,min,sAsIntegermax=0min=100s=0Dima(30)AsIntegerText1.Text=""Text2.

PrivateSubCommand1_Click()Dima%(1To20),max%,min%max=50min=100RandomizeClsFori=1To20a(i)=Int(Rnd*51+5

先在窗体上添加一个TextBox文本框（将其Multiline属性设置为True,并调整宽高以便能较好的显示出100个随机数）和一个Button按钮.然后双击Button按钮跳转到代码编辑窗口,粘帖以

我已经上机验证过了,正确.思路：产生80个随机数,把这80个随机数由小到大排序,然后从第1个到第80个的顺序挑选偶数,赋值给字符串s1,够10个换行.再从第80个到第1个的顺序挑选奇数,赋值给字符串s

PrivateSubCommand1_Click()Dima(1To10)AsIntegerRandomizeFori=1To10a(i)=Int(Rnd*100)+1Printa(i);NextPr

这是我做的,你参考一下.

Java源程序：importjava.util.Random;publicclassTest21{\x05publicstaticvoidmain(String[]args){\x05\x05int[

#includevoidmain(){inta[100],i;for(i=0;i

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PrivateSubCommand1_Click()Dima(100)AsInteger,xAsIntegerFori=1To100Ifsushu(i)ThenPrinti;IfiMod10=0The

源代码已发.278700294@qq.com

#include#include#include#defineMAX100voidqicksort(int*a,int,int);voidchoosesort(int*a,int,int);voidi

PrivateSubCommand1_Click()Dima(29)AsInteger,tmpAsIntegerDimiAsInteger,jAsIntegerRandomizeTimeFori=0T

inta[]={2,5,22,666,33,234,6,7,88,55};intc;//for(inti=0;i

#include <stdlib.h>#include <time.h>#include <stdio.h>void mai

PrivateSubCommand1_Click()Dima,b,cAsIntegerRandomizea=Int(Rnd*9)+1Randomizeb=Int(Rnd*9)+1Randomizec=