分解因式x平方 xy-6y平方 x 13y-6
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原式=(x-y)²-2(x-y)+1=(x-y-1)²
X平方+2XY+Y平方-2X-2y-3=(x+y)^2-2(x+y)-3=(x+y-3)(x+y+1)
原式=(x+y)(x-y)/(x-y)^2=(x+y)/(x-y)=120/100=1.2^2指平方
(x-y)(x-y-2)-3
3x(x^2-2)y^2+6xy^2+9x^2y^2再问:O(∩_∩)O谢谢再答:原式=3x^3-6x^2y+3xy^2提取公因式,得3x(x^2-2xy+y^2)由完全平方公式,得3x(x-y)^2
x³y³—2x²y²+xy=xy(x²y²-2xy+1)=xy[(xy)²-2xy+1]=xy(xy-1)²
6xy^2-9x^2y-y^3=-y(-6xy+9x^2+y^2)=-y(9x^2-6xy+y^2)=-y(3x-y)^2
xy(x-y)-x(x-y)平方=(x-y)[xy-x(x-y)]=(x-y)[2xy-x^2]=(x-y)*x(2x-y)-a平方+1.9b平方=(b根号1.9+a)(b根号1.9-a)-12xy+
双十字相乘.
由x³-2x²y+xy²-x=x(x²-2xy+y²-1)=x[(x-y)²-1]=x(x-y-1)(x-y+1).再问:分解因式:-49x
1x²+2xy-3y²=x²+2xy+y²-4y²=(x+y)²-(2y)²=(x+y+2y)(x+y-2y)=(x+3y)(x-
12x的平方+xy--6y的平方=(3x-2y)(4x+3y)十字相乘3x﹣2y×4x3y
=7x²-4x²+4xy-y²=7x²-(2x-y)²=(√7x+2x-y)(√7x-2x+y)本题答案不唯一的
1)2x²+3x-6有两种方法(1)求根法对于关于x的方程ax²+bx+c=0,若x1,x2是其两根那么ax²+bx+c=a(x-x1)(x-x2)设2x²+3
用反证法.假设此多项式能够分解成两个一次因式的积.设x^2-xy+y^2+x+y=(x+ay+b)(x+cy+d)x^2-xy+y^2+x+y=(x+ay+b)(x+y+d)=x^2+(b+d)x+(
x³y-2x²y+xy=xy(x²-2x+1)=xy(x-y)²
x平方-2xy-3y平方+3x-5y+2=(x²-2xy-3y²)+(2x-6y)+(x+y)+2=(x-3y)(x+y)+2(x-3y)+(x+y)+2=(x-3y)(x+y+2
2x的平方-xy-6y的平方=(2x-3y)(x+2y)
-3x的平方+6xy-3y的平方=-3(x²-2xy+y²)=-3(x-y)²请点击下面的【选为满意回答】按钮,