分解因式:(xy×y)-2xy 2y-4-搜答案-智慧作业帮

(xy-1)^2+(x+y-2)(x+y-2xy)=(xy-1)^2+(x+y)^2-2(xy+1)(x+y)+4xy=(xy+1)^2+(x+y)^2-2(xy+1)(x+y)=[（xy+1)-(x

（1-x^2)(1-y^2)+4xy=1-x²-y²+x²y²+4xy=（x²y²+2xy+1）-（x²-2xy+y²）

壹点丶dream：-2xy-x²-y²=-(2xy+x²+y²)=-(x+y)²

2xy+9-x^2-y^2=9-x^2-y^2+2xy=9-(x^2+y^2-2xy)=9-(x-y)^2=[3-(x-y)][3+(x-y)]=(3-x+y)(3+x-y)

解2x²y-x³-xy²=x(2xy-x²-y²)=-x(x²-2xy+y²)=-x(x-y)²

原式=xy(y-2)+2(y-2)=(y-2)(xy+2)

原式=y（x2+2x+1）=y（x+1）2，故答案为：y（x+1）2．

设t=xy+1;(xy+1)(x+1)(y+1)+xy=t(x+1)(y+1)+xy=t(xy+x+y+1)+xy=t(t+x+y)+xy=t^2+xt+yt+xy=(t+x)(t+y)-xy+xy=

12x^2+xy-6y^2=(4x+3y)(3x-2y)

令x+y=a,xy=b原式化为：（b-1）^2+(a-2)(a-2b)=b^2-2b+1+a^2-2a-2ab+4b=b^2+2b+1+a^2-2a-2ab=(a^2-2ab+b^2)+2(b-a)+

你第一个是不是写错了?[2][(x-1)(y-1)]^2[3](x^3-x+1)(x^2+x+1)

xy(y-2)+2(y-2)=(y-2)(xy+2)

是不是x^3y+x^2y+2xy^2-4xy^3原式=xy(x^2-4y^2)+x^2y+2xy^2=xy(x+2y)(x-2y)+xy(x+2y)=xy(x+2y)(x-2y+1)

=(x²-2xy+y²)²=(x-y)的4次方

这个题目看结构,应该是出错了,好像应该是(x^2-2xy)^2+2y^2(x^2-2xy)+y^4只有这样,才能形成完全平方公式(x^2-2xy)^2+2y^2(x^2-2xy)+y^4=(x^2-2

x²+2xy+y²-1=(x+y)²-1=(x+y+1)(x+y-1)

x^2-xy+y^2 分解因式

你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=（x-y/2）^2+3y^2/4恒大于0,无法分解

9-x^2+2xy-y^2=9-(x-y)^2=[3-(x-y)][3+(x-y)]=(3-x+y)(3+x-y)

原式=(x+y)(x+y)+2(x+y)xy+(xy)^2-1^2=(x+y)^2+2(x+y)xy+(xy)^2-1=(x+y+xy)^2-1=(x+y+xy-1)(x+y+xy+1)=(x+y+x

x^2-2xy+y^2-9=(x-y)^2-9=(x-y+3)(x-y-3)