分解因式(x^2 y^2)-4x^2y^2-搜答案-智慧作业帮

x²-4y²+x-2y=(x²-4y²)+(x-2y)=(x-2y)(x+2y)+(x-2y)=(x-2y)(x+2y+1)很高兴为您解答,祝你学习进步!【学习

a(y-x)-2b(x-y)=a(y-x)+2b(y-x)=(y-x)(a+2b)

（1-x^2)(1-y^2)+4xy=1-x²-y²+x²y²+4xy=（x²y²+2xy+1）-（x²-2xy+y²）

9(x-y)^2+12(x^2-y^2)+4(x+y)^2=[3(x-y)]^2+2*3(x-y)*2(x+y)+[2(x+y)]^2=[3(x-y)+2(x+y)]^2=(5x-y)^2

2x(4-y)再问：麻烦写下过程

解2x²y-x³-xy²=x(2xy-x²-y²)=-x(x²-2xy+y²)=-x(x-y)²

x^2-x-4y^2+2y=(x^2-4y^2)-(x-2y)=(x+2y)(x-2y)-(x-2y)=(x-2y)(x+2y-1)

是不是这样的题目4x^3-4x^2y-(x-y)=(4x^2-1)x-(4x^2-1)y=(4x^2-1)(x-y)=(2x+1)(2x-1)(x-y）

分解因式x^4-x^2+1

x^4-x^2+1=x^4+2x^2+1-3x^2=(x^2+1)^2-3x^2=(x^2+1+√3x)(x^2+1-√3x)

=[2（a-b)]^2-(x-y)^2=(2a-2b+x-y)（2a-2b-x+y)

(x-2)(x+3)+4=(x-2)[(x-2)+5]+4=(x-2)^2+5(x-2)+4=[(x-2)+4][(x-2)+1]=(x+2)(x-1)提示：本题的关键在于把x-2看做整体.或者先展开

原式=[3(x+y)]²-(x-y)²=[3(x+y)+(x-y)][3(x+y)-(x-y)]=(4x+2y)(2x+4y)=4(2x+y)(x+2y)

x^2-xy+y^2 分解因式

你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=（x-y/2）^2+3y^2/4恒大于0,无法分解

原式=(x+y)(x-y)[(x+y)(x-y)-(x²+y²)]=(x+y)(x-y)(x²-y²-x²-y²)=-2y²(x+

x^4-y^4+4x^2+4（分组分解法）=(x^4+4x^2+4)-y^4=(x^2+2)^2-y^4（公式法）=(x^2+2+y^2+2)(x^2-y^2+2)(公式法)4x^2-12xy-c^2

(x+y)^4+(x+y)^2-20＝[﹙x＋y﹚²＋5﹚][﹙x＋y﹚²－4]＝﹙x²＋2xy＋y²＋5﹚﹙x＋y－2﹚﹙x＋y＋2﹚

(2x+y)^2-(x+2y)^2=[(2x+y)-(x+2y)][(2x+y)+(x+2y)]=(2x+y-x-2y)(2x+y+x+2y)=(x-y)(3x+3y)=3(x-y)(x+y)

x^4+x^2-20=(x^2+5)(x^2-4)=(x^2+5)(x+2)(x-2)

用提取公因式法,提取（x+3y)原式=（x+3y)[(3x-4y)-(x-2y)]=(x+3y)(2x-2y)=2(x+3y)(x-y)

(x+2y)²+x+2y=（x+2y)²+(x+2y)=(x+2y)(x+2y+1）