分解因式(xy-y) 6x(y-x)^3

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分解因式x²-xy-2y²-3x+6y

原式=(x-2y)(x+y)-3(x-2y)=(x-2y)(x+y-3)

分解因式x²-6xy-5y²

原式=x²-6xy+9y²-14y²=(x-3y)²-14y²=(x-3y+√14y)(x-3y-√14y)

再问一题分解因式2x^2+xy-y^2-4x+5y-6

2x^2+xy-y^2-4x+5y-6=(2x-y)(x+y)-4x+5y-6=(2x-y)(x+y)+(2x+2y)-6x+3y-6=(2x-y)(x+y)+2(x+y)-6x+3y-6=(x+y)

分解因式的3道题目1 分解因式2x²+7xy+2y²-5y-22 分解因式6x²-13xy

2.6x²-13xy+6y²+22x-23y+20=(2x-3y)(3x-2y)+22x-23y+4×5=(2x-3y+4)(3x-2y+5)3.(x²+4x+8)

-x立方y+6x方y-8xy(十字相乘法分解因式)

-x立方y+6x方y-8xy=-xy(x^2-6x+8)=-xy(x-2)(x-4)

分解因式:x²+3xy+2y²+5x+7y+6

x²+3xy+2y²+5x+7y+6=(x+2y)(x+y)+5x+7y+6十字相乘x+2y+3x+y+2=(x+2y+3)(x+y+2)或是用双十字相乘x²+3xy+2

分解因式:x^2+3xy+2y^2+5x+8y+6

x^2+3xy+2y^2+5x+8y+6=(x+y)(x+2y)+5x+8y+6=(x+y+3)(x+2y+2)x+y3x+2y2

分解因式:x^+3xy+2y^+5x+8y+6

分析由于(x2+3xy+2y2)=(x+2y)(x+y),若原式可以分解因式,那么它的两个一次项一定是x+2y+m和x+y+n的形式,应用待定系数法即可求出m和n,使问题得到解决.解设x2+3xy+2

分解因式2x+xy-y-4x+5y-6

2x^2+xy-y^2-4x+5y-6=(2x-y)(x+y)-4x+5y-6=(2x-y)(x+y)+(2x+2y)-6x+3y-6=(2x-y)(x+y)+2(x+y)-6x+3y-6=(x+y)

分解因式4x^2-12xy+9y^2-2x+3y-6

4x^2-12xy+9y^2-2x+3y-6=(4x^2-12xy+9y^2)-(2x-3y)-6=(2x-3y)^2-(2x-3y)-6=(2x-3y+2)(2x-3y-3)

分解因式x^2-6xy+9y^2-2x+6y=

x^2-6xy+9y^2-2x+6y=(x^2-6xy+9y^2)-(2x-6y)=(x-3y)^3-2(x-3y)=(x-3y)(x-3y-2)

分解因式 3x^3+2x^2y-19xy^2+6y^3

3x^3+2x^2y-19xy^2+6y^3=(3x^3-x^2y)+(3x^2y-19xy^2+6y^3)=x^2(3x-y)+y(3x-y)(x-6y)=(3x-y)(x^2+xy-6y^2)=(

用换元法分解因式 (xy+1)(x+1)(y+1)+xy

设t=xy+1;(xy+1)(x+1)(y+1)+xy=t(x+1)(y+1)+xy=t(xy+x+y+1)+xy=t(t+x+y)+xy=t^2+xt+yt+xy=(t+x)(t+y)-xy+xy=

12x^2+xy-6y^2 怎么分解因式

12x^2+xy-6y^2=(4x+3y)(3x-2y)

分解因式:6x^3-5x^2y-3xy^2+2y^3

6x^3-5x^2y-3xy^2+2y^3=6x^2*(x-y)+x^2y-xy^2-2y^2(x-y)=6x^2*(x-y)+xy(x-y)-2y^2(x-y)=(x-y)(6x^2+xy-2y^2

分解因式:x^2+xy-6y^2-6x+2y+8

x^2+xy-6y^2-6x+2y+8=(x-2y)(x+3y)-(2x+6y)-(4x-8y-8)=(x-2y)(x+3y)-2(x+3y)-4(x-2y-2)=(x+3y)(x-2y-2)-4(x

x^2-xy+y^2 分解因式

你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=(x-y/2)^2+3y^2/4恒大于0,无法分解

分解因式:3x²-6xy-3y

3x²-6xy-3y=3(x²-2xy-y)你的题目是不是错了啊,估计是3x²-6xy+3y²3x²-6xy+3y²=3(x²-2

分解因式计算6x³y(x-y)³-4xy³(y-x)²

6x³y(x-y)³-4xy³(y-x)²=6x³y(x-y)³-4xy³(x-y)²=2xy(x-y)²[3