分式方程1 X=3 2X-4简化时两边乘式
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/14 15:18:32
x/(x-2)-2/(x^2-4x+4)=1x/(x-2)-2/{(x-2)(x-2)}=1因为(x-2)不等于0所以约去x-2得x-2/(x-2)=1同分母得{x(x-2)-2}/(x-2)=1x(
变为5-x/x-4-1/x-4=1两边同乘以x-4得5-x-1=x-4移项河滨并同类项得2x=8解得x=4当x=4是x-4=0所以x为增根所以原方程无解.
乘以x-4得x-5+2(x-4)=-1x-5+2x-8=-13x=13-13x=12x=4检验:x=4时,分母x-4=0,为增根所以原方程无解
你表达的方程的意思是不是x/(x-2)-1=1/(x²-4)那么等式两边同时乘以x²-4,得到x*(x+2)-x²+4=1于是2x=-3解得x=-3/2
(5-x)/(x-4)+1/(4-x)=1==>(5-x)/(x-4)-1/(x-4)=1==>(4-x)/(x-4)=1==>-1=1所以,原方程无解!
Х=1再问:过程?再答:(6x-1)×(2x-5)=(4x-7)×(3x+2)然后拆开,简化最后就得答案了再问:能不能帮忙检验一下,我刚才检验一下,好像不等于1再答:把1带进去,就可以了再问:可代进去
(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)
提负号后,方程两边同乘(x+1)(x-1)得到3(x+1)-4x=-(x-1),化简的3=1,不成立,即此方程无解
两边乘以(x+1)(x-1)得4-(x-2)(x+1)=-(x+1)(x-1)4-x²+x+2=-x²+1x=-5检验:x=-5是方程的解
两边乘以(x+1)(x-1)得x+1-2(x-1)=4x+1-2x+2=4-x=1∴x=-1检验:x=-1是增根∴方程无解
令x-2/x=t,则t^2-2t+1=0,t=1,所以x-2/x=1,即x^2-x-2=0,解得x=2,或x=-1
令x2+2x-8=y,方程化为1y+9x+1y-1y−15x=0,即9x+2yy(y+9x)=1y−15x,解得:y=9x或y=-5x,当y=9x时,x2+2x-8=9x,解得:x1=8,x2=-1;
第三项的分母是x^2-2x-1吧?2x^2-4x-3/(x^2-2x-1)=32x^2-4x-3-3/(x^2-2x-1)=02(x^2-2x-1)-1-3/(x^2-2x-1)=02(x^2-2x-
1/(x-1)(x-2)=1/(x-4)(x-5)(x-1)(x-2)=(x-4)(x-5)x^-3x+2=x^2-9x+206x=18x=3
方程两边同乘(x+1)(x+2)(x+3)(x+4),得(x+3)(x+4)+(x+1)(x+4)+(x+1)(x+2)=(x+1)(x+2)(x+3),∴3x2+15x+18=(x+1)(x+2)(
(x-2)/(x+2)=(x+2)/(x-2)+16/(x²-4)方程两边同时乘(x²-4)(x-2)²=(x+2)²+16x²-4x+4=x
(5x-4)/(x-2)=(4x+10)/3(x-2)-1两边乘3(x-2)3(5x-4)=4x+10-3(x-2)15x-12=4x+10-3x+615x-12=x+1614x=28x=2经检验,x
(1/x+4)+(1/x+6)=(1/x+3)+(1/x+7)1/(x+4)-1/(x+3)=1/(x+7)-1/(x+6)(x+3-x-4)/(x+4)(x+3)=(x+6-x-7)/(x+7)(x
1/x+6+1/x+4=1/x+7+1/x+31/x+6-1/x+7=1/x+3-1/x+41/(x+6)(x+7)=1/(x+3)(x+4)(x+3)(x+4)=(x+6)(x+7)x^2+7x+1