先化简在求值:m-3 3m^2-6m-搜答案-智慧作业帮

原式=9-m2+m2-6m-7=-6m+2=-6*1/2+2=-1

m²-m分之m²-2m+1=(m-1)²/m(m-1)=(m-1)/m=(92-1)/92=91/92

1/2再问：要过程再答：m^2-1=(m-1)(m+1)m^2+4m+3=(m+1)(m+3)1-2m+m^2=(m-1)^2剩下的很简单，自己化简

化简,16m-6m-16m+2-8,所以=-6m-6把m=-1代入得,0

(m^3-2m^2+m)/(m^3-m)=(m^2-2m-1)/(m^2-1)=(m-1)^2/(m-1)(m+1)=(m-1)/(m+1)=2010/2012

原式=（m-3）／[3m（m-2）]·[﹙m+2﹚﹙m+2﹚-5]／﹙m-2﹚=（m-3）／[3m（m-2）]·（m-2）／[﹙m+2﹚﹙m+2﹚-5]=（m-3）／3m[﹙m²-4﹚-5]

-2（mn-3m^2）-m^2+5（mn-m^2）+2mn=-2mn+6m^2-m^2+5mn-5m^2+2mn=5mn当m=1,n=-2时原式=5×1×（-2）=-10再问：谢谢。你是个好人啊

8m的平方-2（3m+4m的平方-1）-8=8m²-6m-8m²+2-8=-6m-8=-6×(-1)-8=6-8=-2

(2m-m^2n)/(m^2n^2-4).=[m(2-mn)]/[(mn+2)(mn-2)]=-m/(mn+2)=-2/(-4)=1/2

m^2-n^2/2m-2n=(m+n)(m-n)/2(m-n)=(m+n)/2=(7-3)/2=2

（2m-n）分之m

x²+3x-1=0符号正确吗?一次项系数为-3,就能求出来再问：正确的再答：原式=（m-3）／[3m（m-2）]·[﹙m+2﹚﹙m+2﹚-5]／﹙m-2﹚=（m-3）／[3m（m-2）]·（

原式＝m/(m+3)-6/(m+3)(m-3)/2/(m-3）=m/(m+3)-3/(m+3)=(m-3)/(m+3).

原式={(m-1)²/[(m-1)(m+1)]}÷[(m-1)(m+1)/(m+1)-(m-1)/(m+1)]=[(m-1)/(m+1)]÷[m(m-1)/(m+1)]=[(m-1)/(m+

=m^2-n^2+m^2+2mn+n^2-2m^2=2mn=2*3*(-1)=-6再问：因式分a的3次方-3a的2次方-10a再答：=a(a^2-3a-10)=a(a-5)(a+2)

=3m^2-m-m^2+9+2(m^2-2m+1)=-5m+11将m=2代入,得：-10+11=1则原代数式值为1.

m(3m-1)-(m+3)(m-3)-2(m-1)^2=3m^2-m-(m^2-9)-2(m^2-2m+1)=3m^2-m-m^2+9-2m^2+4m-2=3m^2-m^2-2m^2-m+4m-2+9

=(m^2-n^2)(-m^2-n^2)-(4m^2-n^2)(4m^2+n^2)=-(m^4-n^4)-(16m^4-n^4)=-（1^4-（-2)^4）-(16*1^4-(-2)^4)=15

原式=m+12m(m−1)•4m2(m+1)2-m+1−m+1(m+1)(m−1)=2m(m−1)(m+1)-2(m+1)(m−1)=2m−2(m+1)(m−1)=2m+1，当m=2时，原式=22+1

我怀疑你少一个平方m/(m+3)-6/(m-9)÷2/(m-3)=m/(m+3)-6/(m+3)(m-3)×(m-3)/2=m/(m+3)-3/(m+3)=(m-3)/(m+3)当m=-2时原式=(-