先化简,在求值 x加1分之1-1减x分之1除以1-x方分之x方-搜答案-智慧作业帮

题目有误吧(x-x)x-1分之4(x-x)+(x-2)再问：(x方-x)(x-2)方再答：

原式=【x(x+1)-x】/(x+1)÷【x²-1+1】/(x²-1)=x²/(x+1)÷x²/(x+1)(x-1)=x-1代入x=1原式=1-1=0如果本题有

=(x²-x-x)/(x+1)÷(x²-1+1)/(x+1)(x-1)=x(x-2)/(x+1)×(x+1)(x-1)/x²=(x-2)(x+1)/x取x=2则原式=0

1、=3(x+2)-x=3x+6-x=2x+6把x=-3/2代入得=-3+6=32、2x+y=5x-3y=5(2)*22x-6y=10(3)(1)-(3)7y=-5y=-5/7代入（2）得：x=5+1

(x+1)(x+2)/(x²+4x+4)×(3x+6)/(2x²-8)×6÷1/(x²-4)=(x+1)(x+2)/(x+2)²×2(x+2)/2(x+2)(x

(x+1)分之1-(x²-6x+9)分之(3-x)÷(x-3)分之(x²+x)=(x+1)分之1-(x-3)²分之[-(x-3)]÷(x-3)分之[x(x+1)]=(x+

(1-x)/(x+2)+(x²+2x+1)/2÷(x²-1)/x-1=(1-x)/(x+2)+(x+1)²×(x-1)/(x+1)(x-1)=(1-x)/(x+2)+(x

(x²+x-2)分之(1+x)÷[x-2+(x+2)分之3]=(x²+x-2)分之(1+x)÷[(x+2)分之(x²-1)]=[(x+2)(x-1)]分之(1+x)×(x

[(2-x)分之1+1]÷(x²-4)分之(x-3)×(x²+4x+4)分之x={(x-2)分之[-1+(x-2)]}÷[(x+2)(x-2)]分之(x-3)×(x+2)²

原式=[3x/(x-1)-x/(x+1)]×[(x²-1)/x]={3x(x+1)/[(x-1)(x+1)]-x(x-1)/[(x-1)(x+1)]}×[(x-1)(x+1)/x]=[3x(

原式=4x²+4x-4x²+1=4x+1=4*(-1/2)+1=-2+1=-12^12-1=(2^6+1)(2^6-1)=65×63所以是65和63

原式=2x/(x²-4)-1/(x-2)=2x/(x²-4)-(x+2)/(x²-4)=(2x-x-2)/(x²-4)=(x-2)/(x²-4)=1/

=x^2+5x-1=1/9-5/3-1=-23/9

估计楼主的意思应该是这样,希望下次提问能知道用图片来表明这种题目

规范而详细解答过程看图,明白就采纳,祝马年学习进步

1/(x-3)+6/(9-x^2)=1/(x-3)+6/(3-x)(3+x)=(x+3-6)/(x-3)(x+3)=1/(x+3)=1/(-2)=-1/2

2(x+x²y)-3分之2(6x²y+3x)-y=2x+2x²y-4x²y-2x-y=-2x²y-y=-2×1²×3-3=-9