先化简,再求值:a+根号1-2a+a的平方-搜答案-智慧作业帮

再问：追我追到这儿了哈

原式=3a/(a-1)*(a+1)(a-1)/a-a(a+1)*(a+1)(a-1)/a=3(a+1)-(a-1)=3a+3-a+1=2a+4当a=√2-2时,原式=2*（√2-2）+4=2√2答：所

原式=(a-b)/a÷[(a²-2ab+b²)/a]=(a-b)/a×a/(a-b)²=1/(a-b)=1/(√3+1-√3+1)=1/2

因为a=根号5+1/2所以：（a-根号3）（a+根号3）-a(a-6)＝a^2－3－a^2＋6a＝6a－3＝6（√5＋1/2）－3＝6√5＋3－3＝6√5

1.(a-√3)(a+√3)-a(a-6)=a^2-3-a^2+6a=6a-3=6(√5+1/2)-3=6√5+3-3=6√52.x^2-5x=14(2x-1)(x-1)-(x+1)^2+1=2x^2

[3a/(a-1)-a/(a+1)]*(a^2-1)/a=a[3/(a-1)-1/(a+1)]*(a^2-1)/a=[3/(a-1)-1/(a+1)]*(a^2-1)=[3(a+1)-(a-1)]/[

运用法则化简,把值带进去就行了

(2a+1)²-2(2a+1)+1=[(2a+1)-1]²=(2a)²=4a²=4*(√2/2)²=4*1/2=2如仍有疑惑,欢迎追问.祝：

原式=（a+1）*（a-1）/(a-1)-根号（a-1）²/(a(a-1))=a+1-1/a=-根号（3-2）+1+1/根号（3-2）=1

.((a平方-2ab+b平方)/(a平方-b平方))/(1/a-1/b)={(a-b)^2/[(a-b)(a+b)]}/[(b-a)/ab]=[(a-b)/(a+b)]*ab/(b-a)=-ab/(a

a=根号2-1∴a-1

a-1分之根号下a的平方-2a+1+a+1分之1+1=√(a-1)²/(a-1)+1/(a+1)+1=-1+1/(a+1)+1=1/(a+1)=1/(√2)=√2/2;再问：当x时，x分之根

根号下3Xa+2X根号下a-aX根号下a-2X根号下a等于根号下3Xa-aX根号下3把a=3代入结果等于0肯定对一定要采纳啊

(a-根号3）（a+根号3）-a(a-6)=a²-3-a²+6a=-3+6a=-3+12=9mx的平方-6mx+9m=m(x²-6x+9)=m(x-3)²3ab

2/a-1+（a^2-4a+4）/（a^2-1）×a+1/a-2=2/(a-1)+(a-2)²/(a+1)(a-1)×(a+1)/(a-2)=2/(a-1)+(a-2)/(a-1)=a/(a

（a+2a+1）/（a-1）-a/(a-1)=(a+1)^2/(a+1)(a-1)-a/(a-1)=(a+1)/(a-1)-a/(a-1)=1/(a-1)由a=根号3+1,所以原式=1/(a-1)=1

答：a=1/(2+√3)=(2-√3)/[(2+√3)(2-√3)]=(2-√3)/(4-3)=2-√3所以：0

4a（a+1）+（a-2）2=4a*a+4a+2a-4=4a*a+6a-4将a＝根号5代入原式=4*5+6*根号5-4=16+6*根号5

(2a/(a+b)(a-b))xa+b/ab=2(a+b)/(a-b)=2(2√2+1)=4√2+2