先化简,再求值:(m n)的2平方 (m n)
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/22 01:04:48
原式=-2mn+6m²-m²+5(mn-m²)-2mn,=-2mn+6m²-m²+5mn-5m²-2mn,=mn,当m=1,n=-2时,原式
原式=4(m²-2mn-1/4n²)-(4m²-n²)=4m²-8mn-n²-4m²+n²=-8mn=4再问:[(2x^
再答:错了再答:后面是3(m-n)再答:是15+12=27再问:谢谢了
2(mn+m)-[-(3n-mn)-m]+mn =2mn+2m+3n-mn+m+mn =2mn+3m+2n =2mn+3(m+n) ∵m+n=3,mn=-2 ∴2(mn+m)-[-(3n-m
m/(m-n)-n/(m+n)+2mn/(m²-n²)=[m(m+n)-n(m-n)+2mn]/(m²-n²)=(m²+n²)/(m
-2(mn-3m²)-[m²-5(mn-m²)+2mn]=-2mn+6m²-m²+5(mn-m²)-2mn=-2mn+6m²-m&
把括号都拆开即可原式=-2mn+6m²-m²+5(mn-m²)-2mn=-2mn+6m²-m²+5mn-5m²-2mn=mn当m=1、n=-
原式=(3m-n)²分之m(3m-n)=(3m-n)分之m=(3*1-2)分之1=1
=1+√N+√(MN)=1+√2+√6
-2(mn-3m^2)-m^2+5(mn-m^2)+2mn=-2mn+6m^2-m^2+5mn-5m^2+2mn=5mn当m=1,n=-2时原式=5×1×(-2)=-10再问:谢谢。你是个好人啊
[(-3mn)^2*m^3-2m^2(3mn^2)^3*0.5n]/(-3m^2n)^2=[9*m^2*n^2*m^3-2*m^2*27*m^3*n^6*0.5n]/(9*m^4n^2)=m-3mn^
原式=[(-3mn)^2*m^3-2m^2*(3mn^2)^3*n/2]÷(-3m^2n)^2=(9m^2n^2*m^3-2m^2*27m^3n^6*n/2)/(9m^4n^2)=9m^5n^2/(9
原式=[(2m-n)^2]/[m(2m-n)]=(2m-n)/m当m=1,n=-2时原式=[2-(-2)]÷1=4÷1=4^表示平方再问:还是你的标准一点,采纳你吧
(2m-n)分之m
(mn-m²)÷(m²-2mn+n²)/mn·(m²-n²)/m²=m(n-m)×mn/(m-n)²×(m+n)(m-n)/m
2m的平方-3mn-n的平方-2mn-2m的平方+5mn-2n+1=-n的平方-2n+1=-1/4+1+1=7/4
2m-(n+1)+(m²-2mn+n²-1)/m-n-1=2m-n-1+(m-n+1)(m-n-1)/(m-n-1)=2m-n-1+m-n+1=3m-2n=6-6=0
[(3m-n)^2-(3m-n)(3m+n)-4mn]/(2n)=[(9m²+n²-6mn)-(9m²-n²)]/(2n)=(9m²+n²-