先化简,再求值(x+3分之2+3-x分之1)除以x²-9分之x

原式=[3x(x+1)-x(x-1)/x^2-1]×(x^2-1/2x)上面化到最后=[2x(x+2)/x^2-1]×x^2-1/2x=x+2当x=3时,原式=-3+2=-1(在键盘上打这个好辛苦啊~

x的平方-2+x分之1-x除以(x-2+x+2分之3),其中x等于2分之1=(1-x)/(x²-2+x)÷[x-2+3/(x+2)]=(1-x)/(x+2)(x-1)÷(x²-4+

x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1=[x/(x+2)-(x²+2x+1)/(x+2)]÷(x²-1)/(x-1)=[(x-x²-2x-1)/

x/(x-3)-3x/(x^2-3x)-3/x通分得=x^2/(x^2-3x)-3x/(x^2-3x)-3*(x-3)/(x^2-3x)=(x^2-3x-3x+9)/(x^2-3x)=(x-3)(x-

先化简,再求值:(x平方-1)分之(3x-3)÷(x+1)分之(3x)-(x+1)分之1,其中x=2=3(x-1)/(x+1)(x-1)×(x+1)/(3x)-1/(x+1)=1/x-1/(x+1)=

(x-1分之x平方-1-x分之2x)除以x-1分之x,其中x=根号3+1=[x²/(x-1)+2x/(x-1)]÷x/(x-1)=x(x+2)/(x-1)*(x-1)/x=x+2其中x=根号

x+4>0x>-42x+5

x的3次方-2x[2分之1x的平方-3(3分之1x-1)],其中x=-2分之1=x³-x³+6x(3分之1x-1)=2x²-6x=2*(-1/2)²-6*(-1

1、(x-3分之2x-x+3分之x)乘x分之x平方-9=［2X(X+3)-X(X-3)］/［(X-3)(X+3)］*(X+3)(X-3)/X=［2X^2+6X-X^2+3X］/X=X+9当X=1时,原

{1+[(x+1)(x-2)]分之(2x-4)}/(x的平方-1)分之(x+3)=[(x+1)(x-2)]分之（x²-x-2+2x-4）×(x+3)分之(x²-1)=(x-2)分之

（x-1分之3x-x+1分之x）*x分之x的平方-1=[3x(x+1)-x(x-1)]/x=3(x+1)-(x-1)=3x+3-x+1=2x+4=2√2-4+4=2√2再问：确定么再答：确定啊，楼下也

,(X-2-X+2分之5)/2x+4分之x-3=[(x-2)(x+2)-5]/(x+2)×2(x+2)/(x-3)=(x²-9)/(x+2)×2(x+2)/(x-3)=(x+3)(x-3)/

x²-2x-3=0(x+1)(x-3)=0x=-1或x=3当x=-1时(x-1)分之(x²-3)÷(x-1)分之1=(x-1)分之(x²-3)×(x-1)=x²

您好：x-2＞0x>22x+1＜82x

原式=(x-1)(x+1)/(x+2)*(x+2)/x-1=x+1然后代入数值即可很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

[3x/(x-1)-x/(x+1)]×(x²-1)/x=x[3(x+1)-(x-1)]/(x²-1)×(x²-1)/x=2x+4当x=√2-2时,原式=2x+4=2√2

原式＝[2x(x+2)-x(x-2)]/(x²-4)＋x/(x²-4)＝(x²+7x)/(x²-4)＝[x(x+7)]/[(x+2)(x-2)]代入x＝5原式＝

=（x+1）/（（2*x+1+x^2）/x）=（x+1）/（（x+1）^2/x）=（x+1）*x/（x+1）^2=x/（x+1）代入x=-3/2得到：原式=3

（x²-1分之x-3）÷（x²+2x+1分之x²-2x-3)-(x+1分之1）=(x-3)/(x+1)(x-1)×(x+1)²/(x-3)(x+1)-1/(x+