从键盘上输入一个浮点数,将其结果保留两位小数输出

看vari,j,n,t:longint;a:array[1..1000]oflongint;beginwhilenoteolndobegininc(n);read(a[n]);end;i:=1;j:=

importjava.util.Scanner;publicclassA{//下面的方法是对单个数求阶乘,并返回publicstaticintjieCheng(intn){intsum=1;for(i

intmain(){intn,n1,n2,n3,n4;cin>>n;n1=n/1000;n2=(n%1000)/100;n3=(n%100)/10;n4=n%10;n=n1+10*n2+100*n3+

int交换函数（intX）{int新十位数=X用10取余；int新个位数=（X-[X用10取余]）/10；交换函数=10×新十位数+新个位数；输出“交换函数”}说明：输入的数据为X.

阶乘intmain(){inti,n;doublesum=1;/*定义3个变量,一个自增,一个范围,一个结果*/printf("enteronenumber:");scanf("%d",&n);/*输

#includeusingnamespacestd;intmain(void){floatf;scanf("%f",&f);printf("整数部分:%d\n",int(f));printf("小数部

可以把浮点数当初字符串来处理字符串处理函数如下：voidcut(string&str){intn=0;n=str.size()-1;stringcutter(n,'');stringstr3(n,''

#includeintmain(void){inta,b,c,t;printf("请输入三个数");scanf("%d%d%d",&a,&b,&c);if(a

importjava.util.Scanner;publicclassJiecheng{Scannerin=newScanner(System.in);inta=in.nextInt();int

cin>>x;inta=x/100,b=x/10%10,c=x%10;cout

PrivateSubCommand1_Click()DimA(10)AsLong,IAsLongForI=1To10A(I)=InputBox("请输入第"&I&"个数据","提示","")Print

#includemain(){inta;printf("ÊäÈëÒ»¸öÕý&

n=1sum=0dowhiln

用什么语言编程？参考：http://zhidao.baidu.com/question/983257464781691619.html

#includeusingnamespacestd;voidmain(){chara[10];inti,temp;for(i=0;i>a[i];cout

#includevoidmain(){floata=0,b=0,c=0;chard;printf("输入两个数:\n");scanf("%f%f",&a,&b);getchar();printf("选

#includemain（）{floatp,q；scanf（"%f%f",&p,&q);printf("%f\n“,p+q）；printf("%f\n",p-q）；printf("%f\n",p/q)

importjava.util.Scanner;publicclassInputTest{publicstaticvoidmain(String[]args){Scannerin=newScanner

CLEARaccept"请输入N值："TONs=1FORi=1TOVAL(n)IFMOD(i,2)=0s=s*iENDIFENDFOR?"1——N中的所有偶数的积为："+ALLTRIM(STR(s))

#include"stdio.h"voidmain(){intNum=0;printf("请输入数字：");scanf("%d",&Num);intArray[100];intn_Num=0;//记录