从键盘上输入一个四位数,然后将它反向输出.

intmain(){intn,n1,n2,n3,n4;cin>>n;n1=n/1000;n2=(n%1000)/100;n3=(n%100)/10;n4=n%10;n=n1+10*n2+100*n3+

int交换函数（intX）{int新十位数=X用10取余；int新个位数=（X-[X用10取余]）/10；交换函数=10×新十位数+新个位数；输出“交换函数”}说明：输入的数据为X.

/*12342103Pressanykeytocontinue*/#include<iostream.h>int main() {\x09int digit1

#includeintfun(){inta[3][3],sum;inti,j;sum=0;//sun=0for(i=0;i

#includeusingnamespacestd;intmain(void){floatf;scanf("%f",&f);printf("整数部分:%d\n",int(f));printf("小数部

可以把浮点数当初字符串来处理字符串处理函数如下：voidcut(string&str){intn=0;n=str.size()-1;stringcutter(n,'');stringstr3(n,''

#includevoidmain(){longa;intj,i=0,b[20];scanf("%ld",&a);while(a!=0){b[i++]=a%10;a=a/10;}for(j=i-1;j>

#includemain(){inta;printf("ÊäÈëÒ»¸öÕý&

inti;floatf;doubled;charc;scanf("%d,%f,%f,%c",&i,&f,&d,&c);printf("%d,%f,%f,%c\n",i,f,d,c);doublesum

方法一：//用数学函数#include#includevoidmain(){inta;scanf("%d",&a);printf("%d\n",abs(a));}方法二：//判断#includevoi

#include#includevoidmain(void){inti,j,k,f,z;scanf("%d",&i);if(i

#include<stdio.h>int main(){int n,s=0;scanf("%d",&n);while(n){s=

import java.util.*;public class Demo{    public static 

第1题：PrivateSubCommand1_Click()Dimv(1To20)AsDoubleDimvMaxAsDoubleDimvMinAsDoubleDimiAsLongFori=1To20v

4321-1234=30878765-5678=30879876-6789=3087永远等于3087

#includeusingnamespacestd;voidmain(){chara[10];inti,temp;for(i=0;i>a[i];cout

importjava.util.Scanner;publicclassInputTest{publicstaticvoidmain(String[]args){Scannerin=newScanner

#include"stdio.h"voidmain(){intNum=0;printf("请输入数字：");scanf("%d",&Num);intArray[100];intn_Num=0;//记录

#includeusingnamespacestd;voidmain(){intx,n=0,sum=0;cin>>x;if(x==0)n=1;while(x>0){sum+=x%10;x/=10;n+