(x-1)²-4=0用因式分解法-搜答案-智慧作业帮

因式分解4(x²-1)

=4(x+1)(x-1)

1-4X平方因式分解.

1-4x²=(1-2x)(1+2x)

(x-3)(4x-13）=0

x的平方-4x+4=(2x-1)²(x-2)²-(2x-1)²=0(x-2+2x-1)(x-2-2x+1)=0(3x-3)(-x-1)=0(x-1)(x+1)=0x=1或

e龙葵儿,你好!4x-4x²-1=-（4x²-4x+1）=-（2x-1）²

x^4-x^-2-x+1=x²(x²-1)-(x-1)=(x-1)[x²(x+1)-1】=（x-1）(x³+x²-1);

9X^2-6X+1=0(3X-1)^2=03X-1=0X=1/3

(x-1)^2-4(1-x)+4=0(x-1)^2+4(x-1)+4=0((x-1)+2)^2=0(x+1)^2=0x=-1

3x的平方-4x=0x(3x-4)=0x1=0,x2=4/3

3x^2-48=03(x²-16)=03(x-4)(x+4)=0∴x-4=0或x+4=0x1=4,x2=-4x^2+4=4xx²-4x+4=0(x-2)²=0x1=x2=

4x^2-(x-1)^2=03x^2+2x-1=0(3x-1)(x+1)=0

-5x-2x平方-1=02x²+5x+1=0x²+5x/2+1/2=0x²+5x/2+1/2=(x²+5x/2+25/16)-25/16+1/2=(x+5/4)

x^4+2x^3-4x^2-7x+1=(x-x1)(x-x2)(x-x3)(x-x4)再问：这是什么软件再答：--百度顺手搜的、到处都是。而且百科里有4次方程的求根公式、虽然很长。。。

1/2x²-2x-3=x²-4x+4-4-6=（x-2)^2-10=0(X-2+根号10）（x-2-根号10）=0

4x^2-1=0(2x+1)(2x-1)=02x+1=0或2x-1=0x=-1/2或x=1/2

x²-4x+4-2=0(x-2)²-2=0(x-2+√2)(x-2-√2)=0x=2-√2,x=2+√2再问：你看错题了吧再答：对的采纳再问：是x^2-4x+2=0不是x²

稍等.再答：再答：满意请采纳

(1)-x^4+16因式分解

16-x^4=(4+x^2)(4-x^2)=(4+x^2)(2-x)(2+x)

9(x-1)^2=4(x+1)^29(x-1)²-4(x+1)²=0[3(x-1)+2(x+1)][3(x-1)-2(x+1)]=0(5x-1)(x-5)=05x-1=0或x-5=

解x^4-x^2-20=0(x^2-5)(x^2+4)=0∵x^2+4≠0∴x^2-5=0∴x^2=5∴x=√5或x=-√5

(x-1)²-4=0用 因式分解法