(x y)²减(x-y)²多少等于-搜答案-智慧作业帮

解题思路：本题主要利用完全平方公式进行因式分解即可求出结果解题过程：解:x²－6xy＋9y²=(x-3y)2

√xy+y分之一+√xy+x分之一=√xy(1／x+1／y)=√xy乘[（x+y）／xy]=√xy（x+y）再问：√xy(1／x+1／y)这一步怎样计算？再答：(1／x+1／y)1／x和1／y通分再问

6xy²－9x²y－y³=－y(9x²－6xy＋y²)=－y(3x－y)²

-2,前提是xy都不为零再问：能说一下解题步骤吗？

xy=x-y两边同时除以xy1=1/y-1/xy分之一减x分之一等于1

解题思路：将原方程右边分解因式为（x-4y)(x+y)=0,可得x=4y或x=-y,进而可求出x与y的比值。解题过程：解：∵x2-3xy-4y2=0∴（x-4y)(x+y)=0∴x=4y或x=-y∵x

解析：

x分之1减y分之1等于2（y-x）xy=2y-x=2xyy减xy减x分之3x加xy减3y=[3(x-y)+xy]/(y-x-xy)=(-6xy+xy)/(2xy-xy)=-5xy/xy=-5

令xy=t,则xy/(1-e^xy)=t/(1-e^t),满足洛必塔法则条件,当(x.y)→(0,0)时,limxy/(1-e^xy)=limt/(1-e^t)=lim1/（—e^t）=—1

x²y-xy²=xy(x-y)=3×2=6再问：怎样变为xy(x-y)再答：提取公因式x²y＝(xy)×(x)xy²＝(xy)×(y)都有因式xy，可以提取出来

[2x(x²y-xy²)+xy(xy-x²)]÷x²y=[2x²y(x-y)+x²y(y-x)]÷x²y=2(x-y)+(y-x)

如果题目是:"x的平方减xy分之y加y的平方减xy分之x",那么就是你的那个答案.y/(x^2-xy)+x/(y^2-xy)=y/[x(x-y)]+x/[y(y-x)]=y^2/[xy(x-y)]-x

2(x+xy)-[(xy-3y)-x]-(-xy)=2x+2xy-xy+3y+x+xy=3x+3y+2xy=3（x+y）+2xy=3*（-2）+2*3=0

1/x-1/y=3y-x=3xyx-y=-3xy(5x-xy-5y)/(x-xy-y)=(-15xy-xy)/(-3xy-xy)=4

（x+y)*(x+1)-y(x+y)=(x+y)*(x+1-y)

xy=x-y,因为求1/x-1/y,则x,y不会是0,所以等式两边同时处以xy,xy/xy=(x-y)/xy,1=1/y-1/x,则1/x-1/y=-1

x分之1减y分之1等于31/x-1/y=3(y-x)/xy=3y-x=3xy所以x-xy-y分之5x-xy-5y=（-3xy-xy）分之(-15xy-xy)=-4分之（-16）=4

x^2-3y^2=2xyx^2-2xy-3y^2=0(x-3y)(x+y)=0x=3y或者x=-y当x=3yx+2y=5yx-y=2y所以(x+2y)/(x-y)=5/2当x=-yx+2y=yx-y=

xy/(x+y)=2(x+y)/xy=1/21/x+1/y=1/2(3x-xy+3y)/(-x+3xy-y)=(3/y-1+3/x)/(-1/y+3-1/x)=[3(1/x+1/y)-1]/[(3-(

1/x-1/y=(y-x)/xy=-(x-y)/(x-y)=-1