(5*11X-10) (11X)=(5*7X 10) (7X 4)

如果没看错的话,算出来的值是6,看错后算出的是22差是16可知应该是把-8看成了+8,这样就多出了16故,应该是8x^7这里看错了

1/（x^2-7x+10)+1/(x^2-x-2)+1/(x^2+5x+4)+1/(x^2+11x+28)=[1/(x-5)-1/(x-2)+1/(x-2)-1/(x+1)+1/(x+1)-1/(x+

这是两道题吗?1、两边同时乘(x-1)(x-2)(x-3）答案是x1=-1,x2=22、分母因式分解分别为(x-7)(2x+3)和(x-5)(x-7)然后同时乘(x-5)(x-7)(2x+3)答案是x

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

(x+1)(3x-5)(2x+5)(3x-2)(x+1)(6x-5)(x-1)(6x+5)(2x-1)(3x+5)(2x-1)(3x-5)(2x+1)(3x+5)

【解法一】【解法二】5x(x+7)(x+4)=5x(x^2+11X)5x(x²+11x+28)-5x(x²+11x)=05x^3+55x^2+140x=5x^3+55x^25x(x

3x*x+11x+10＝（3x+5）(x+2)

再问：因式分解？七道？再答：七个都在啊再答：数字我帮你分开了再答：不用谢

5x(x+7)(x+4)=5x(x^2+11X)5x^3+55x^2+140x=5x^3+55x^2140x=0x=0

x(2x-3)+3x+3x(x-2)=5x(x-4)+112x²-3x+3x+3x²-6x=5x²-20x+115x²-6x=5x²-20x+115x

[1/(x-1)(x+2)]+[1/(x+2)(x+5)]+[1/(x+5)(x+8)]+[1/(x+8)(x+11)]=(1/3x-3)-1/24(1/3)[1/(x-1)-1/(x+11)]=1/

原式=[x(x-3)/(x-3)²][(x-5)(x-6)/x(x-5)]-1=[x/(x-3)][(x-6)/x]-1=(x-6)/(x-3)-1=(x-6-x+3)/(x-3)=-3/(

这个因式让其等于0列成方程,用计算机近似求解得x=1.42245到1.42246之间（大概是1.4224565左右）只有这一个实数解.至于在复数域范围内的,就要请教高手了.如果上面的不对还请指教.

x^4+√5x^3-11x^2-√5x+10=x^4-11x^2+10+√5x^3-√5x=(x^2-10)(x^2-1)+√5x(x^2-1)=(x^2-10+√5x)(x^2-1)=(x+1)(x

自己算吧

解2x^2+3x=32x^2+3x-3=0△=b^2-4ac=9+24=33∴x=(-3+√33)/4或x=(-3-√33)/4(2)x^2-2x+1=25(x-1)^2=25∴x-1=±5∴x=6或

看三个分母的因式可以知道：首先,每个提出一个常数,把分子化成简单的常数,即化为：1+1/(x^2+6x+9)+1-2/(x^2-9)+2-1/(x^2+4x+3)接着,每个因式分母提出（x+3）,即为

2x平方+3x=3(用配方)x²+(3/2)x=3/2x²+(3/2)x+(3/4)²=(3/2)+(3/4)²[x+(3/4)]²=33/16x+(

(x^3-7x^2+3x+11)(2x^4-13x^3+5x^2+3x-10)=2x^7-13x^6+5x^5+3x^4-10x^3-14x^6+91x^5-35x^4-21x^3+70x^2+6x^

x^2-2x+1=15(x-1)^2=15x=正负根号15+1x(2x-5)=4x-102x^2-5x-4x+10=02x^2-9x+10=0(2x-5)(x-2)=0x=5/2或x=2x^2+5x+