(36 10%x)÷(120 x)=20%

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[(x+2)/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x

[(x+2)/(x*x-2x)-(x-2)/(x*x-4x+4)]/[(x-4)/x]=[(x+2)/x(x-2)-(x-2)/(x-2)²]/[(x-4)/x]=[(x²-4-x

x²-1/x²-2x+1÷x+1/x-1 X 1-x/1+x

=(x+1)(x-1)(x+1)x-1--------------÷------×-----(x-1)^2(x-1)x+1=x+1---x-1

(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3

(x+1-1/1-x)÷(x-x²/x-1)=[(x+1)+1/(x-1)]×[-(x-1)/x(x-1)]=(x²-1+1)/(x-1)×(-1/x)=-x/(x-1)(x-4/

(x

展开式的通项为Tr+1=(−12)rCr10x30−5r令30-5r=0得r=6故展开式的常数项为(−12)6C610=10532故答案为10532

x-2/x-1÷(x+1-3/x-1)

解题思路:分式的混合运算,按照分式运算法则进行计算。解题过程:

[1-x+(x-1/x)]÷[1-(1/x+1)]

先化简去掉中括号:(1-x+x-1/x)÷(1-1/x-1)再化简:(1-1/x)÷(-1/x)=(1-1/x)x(-x)=1-x

(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)

(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)=2(x-3)/(x-2)^2X(x+3)^2/(3-x)X(2-x)/(x+3)=2(x-

先化简(x平方-4x+4)/(x平方-2x)÷(x-4/x)

(x²-4x+4)/(x²-2x)÷(x-4/x)=(x-2)²/[x(x-2)]÷[(x²-4)/x]=(x-2)²/[x(x-2)]÷[(x+2)

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x-20%x=4 4x-75%=0.25 x÷四分之五=40% 20%x+30%x=120

x-20%x=40.8x=4x=4÷0.8x=54x-75%=0.254x=0.25+75%x=1÷4x=0.25x÷5/4=40%x=40%×5/4x=1/220%x+30%x=120x=120÷0

计算:2x/(x-2)(x+1)÷(1-x/x+1)-x²+2x/x²-4?

2x/(x-2)(x+1)÷(1-x/x+1)-x²+2x/x²-4?=2x/(x-2)(x+1)×(x+1)/(1-x)-x(x+2)/(x+2)(x-2)=2x/(x-2)(1

化简 (3x/x-1 -x/x+1)÷x/x²-1

=【3x(x+1)-x(x-1)]/(x+1)(x-1)×(x+1)(x-1)/x=(3x²+3x-x²+x)/x=4

先化简再求值[3x/(x+2)-x/(x-2)]÷2x/(x^2-4)

[3x/(x+2)-x/(x-2)]÷2x/(x^2-4)分子分母同时乘以x²-4=[3x(x-2)-x(x+2)]/2x=(3x²-6x-x²-2x)/2x=(2x&#

x(120+x)*80%=x-76

需要过程?再问:嗯嗯*^O^*再答:数有点大稍等再问:好的好的^W^再答:问题没错?再问:没错再问:算不出来么?再答:整理出来4x^2+475x+380=0再问:那估计是数抄错了还是要谢谢你^W^

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解题思路:同学你好,本题利用同角三角函数的基本关系求解,具体过程见解析解题过程:

x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)

x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)=x((2x-1)/x)+x/(x^2-2x)x(x^2-4)/(3-x)=(2x-1)+(x+2)/(3-x)=(7x-3-2x^2

(3x*x+3x*x+x*x)*2=120,

7x²*2=120x²=60/7x=-2√105/7,x=2√105/7

1.(1+2/X-X+1/X-2)÷X+4/X²-2X

你的括号丢得太多了,我猜猜猜1、实在猜不出来,哪里该有括号2、2X/(2X-1)+X/(X-2)=2[2X(X-2)+X(2X-1)]/(2X-1)(X-2)=22X^2-4X+2X^2-X=4X^2