(2xy x)×(3x²y-2y) 这个题怎么算..

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计算:(1)2xyx

(1)原式=2xy+x(x−y)+y(x+y)x2−y2=(x+y)2(x+y)(x−y)=x+yx−y;(2)原式=2a−(a+2)(a+2)(a−2)a−2(a+2)(a−2)=1a+2;(3)原

已知xyx+y=2

∵xyx+y=2∴xy=2(x+y)∴原式=3x−5×2(x+y)+3y−x+3×2(x+y)−y=−7x−7y5x+5y=−75

(x-y)^2-(x-y)^3因式分解

(x-y)^2-(x-y)^3=(x-y)^2[1-(x-y)]=(x-y)^2(1-x+y)2.(x+y)^2-(x+y)^3=(x+y)^2[1-(x+y)]=(x+y)^2(1-x-y)3、(x

二元函数求极限3-√9+xy------------xyx.y均趋进于0中间那条虚线暂代分数线

这个应该没有极限,如果有极限,则沿着任何方向极限应该相同.我们取x=y方向逼进,则极限变成一元极限,很显然当xy->0时,分母为0,分子不为0,这种情况必然没有极限再想想,肯定时楼主输入时没有注意加括

计算(x+y)(x+y)^2(-x-y)^3

(x+y)(x+y)^2(-x-y)^3=-(x+y)^6

已知正数x,y满足x2+y2=1,则xyx+y的最大值为(  )

解;已知正数x,y满足,x2+y2=1,则1=x2+y2≥2xy,∴xy≤12…①   又xyx+y=11x+1y≤12 1x•1y=xy2…②①②联立得xyx

已知三个数x,y,z满足xyx+y

∵xyx+y=-2,yzy+z=43,zxz+x=-43,∴1x+1y=-12,1y+1z=34,1z+1x=-34,∴2(1x+1y+1z)=-12,即1x+1y+1z=-14,则xyzxy+yz+

已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y

X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

计算:(-x-2y) * (3x-y)

(-x-2y)*(3x-y)=-3x^2-5xy+2y^2

数学(x-y)^5*(y-x)^3*(x-y)^2

(x-y)^5*(y-x)^3*(x-y)^2=-(x-y)^5*(x-y)^3*(x-y)^2=-(x-y)^(5+3+2)=-(x-y)^10

化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方

(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方=x²-2xy-3y²-x²+4y²-x²+2xy-y²=(x²-

求极限(工本高数)lim [2-(xy+4)^(1/2)]/xyx->0y->0证明函数f(x,y)=(x+y)/(x-

证明函数f(x,y)=(x+y)/(x-y)在点(0,0)处的二重极限不存在.当点(x,y)沿着直线y=kx(k为不等于1的任意实数)趋于(0,0)时,limf(x,y)=lim(x+kx)/(x-k

若实数x,y,z满足方程组:xyx+2y=1…(1)yzy+2z=2…(2)zxz+2x=3…(3),则有(  )

由(1)、(3)得y=xx−2,z=6xx−3,故x≠0,代入(2)解得x=2710,所以y=277,z=-54.检验知此组解满足原方程组.∴10x+7y+z=0.故选D.

[(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y)

=(x-y)[(3x+y)-(2x+3y)]*(x-y)=(x-y)*(x-y)(3x+y-2x-3y)=(x-y)(x-y)(x-2y)到底是化简,还是?=(x*x-2xy+y*y)(x-2y)=x

如果把分式xyx+y中的x和y都扩大2倍,则分式的值(  )

把分式xyx+y中的x和y都扩大2倍后得:2x•2y2(x+y)=4xy2(x+y)=2•xyx+y,即分式的值扩大2倍.故选:B.

先化简,再求值:x2y-[4x2y-(xyz-x2z)-3x2z]-2xyx,其中x的倒数等于其本身,|y|=3,x2=

x=±1,y=±3,z=±2xyzz>y则0>x>z>yx=-1,y=-3,z=-2,x2y-[4x2y-(xyz-x2z)-3x2z]-2xyx=x2y-4x2y+xyz-x2z+3x2z-2xyx

【x-3y][x+y]-[x-2y][x +2y]-[x-y

解题思路:根据题意,由整式的运算的知识整理,分析可以求得解题过程:

有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-

解代数式得:-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!

(x+y)^2-3(x-y)因式分解

(x+y)^2-3(x+y)=(x+y)(x+y-3)